#感知机 ##一、实验目的了解感知机原理用python实现感知机功能 ##二、实验环境蓝桥实验楼，python ##三、实验步骤 (1)阅读实验要求，了解到感知机公式![图片描述](https://dn-simplecloud.shiyanlou.com/courses/uid1531734-20201228-1609155837916)，可知与门0<=θ，w1<=θ,w2<=θ,w1+w2>θ。 (2)同理可根据公式推出与非门满足θ<0,θθ。（3）Q1：与非门```(-0.3，-0.4，-0.5)``` 或门：```（0.8，0.7，0.3）``` (4)打开ide编写代码Q2:根据或门代码可带入满足与非门的条件 ``` def AND(x1,x2): w1,w2,theta = -0.3,-0.4,-0.5 tmp = x1 * w1 + x2 * w2 if tmp <= theta: return 0 elif tmp > theta: return 1 if __name__ == '__main__': for xs in [(0, 0), (1, 0), (0, 1), (1, 1)]: y = AND(xs[0], xs[1]) print(str(xs) + " -> " + str(y)) ``` 运行结果可得 ``` (0, 0) -> 1 (1, 0) -> 1 (0, 1) -> 1 (1, 1) -> 0 ``` Q3:满足或门的条件 ``` def AND(x1,x2): w1,w2,theta = 0.8,0.7,0.3 tmp = x1 * w1 + x2 * w2 if tmp <= theta: return 0 elif tmp > theta: return 1 if __name__ == '__main__': for xs in [(0, 0), (1, 0), (0, 1), (1, 1)]: y = AND(xs[0], xs[1]) print(str(xs) + " -> " + str(y)) ``` 运行结果得 ``` (0, 0) -> 0 (1, 0) -> 1 (0, 1) -> 1 (1, 1) -> 1 ``` (5)学习权重了解权重原理根据公式![图片描述](https://dn-simplecloud.shiyanlou.com/courses/uid1531734-20201228-1609158931195)我们将权重设为θ值，将第四步代码改写为Q4: ``` import numpy as np def AND(x1, x2): x = np.array([x1, x2]) w = np.array([-0.3, -0.4]) b = 0.5 tmp = np.sum(w*x) + b if tmp <= 0: return 0 else: return 1 if __name__ == '__main__': for xs in [(0, 0), (1, 0), (0, 1), (1, 1)]: y = AND(xs[0], xs[1]) print(str(xs) + " -> " + str(y)) ``` 运行结果为： ``` (0, 0) -> 0 (1, 0) -> 0 (0, 1) -> 0 (1, 1) -> 1 ``` 或门Q5: ``` import numpy as np def AND(x1, x2): x = np.array([x1, x2]) w = np.array([0.8, 0.7]) b = -0.3 tmp = np.sum(w*x) + b if tmp <= 0: return 0 else: return 1 if __name__ == '__main__': for xs in [(0, 0), (1, 0), (0, 1), (1, 1)]: y = AND(xs[0], xs[1]) print(str(xs) + " -> " + str(y)) ``` 运行结果为： ``` (0, 0) -> 0 (1, 0) -> 1 (0, 1) -> 1 (1, 1) -> 1 ``` ##四、实验总结感知机从我感觉的数学角度上说就像直角坐标系上的多元函数我们可以设置w值权重实现感知机与非门或门都可以带入(x1,x2)像函数中(0,0)(0,1)(1,0)(1,1)看是否满足与非门或门的公式。从公式上我们可以看出与门与非门或门可套用公式在坐标轴上表示为线性的函数，而遇到异或门这样的非线性曲线的无法用感知机实现

“信息工程学院18级生产实习-Part1”实验报告